如何使用printf格式化unsigned long long int？

Question

#include <stdio.h>

int main() {

    unsigned long long int num = 285212672; //FYI: fits in 29 bits

    int normalInt = 5;

    printf("My number is %d bytes wide and its value is %ul. A normal number is %d.\n", sizeof(num), num, normalInt);

    return 0;

}

输出：

My number is 8 bytes wide and its value is 285212672l. A normal number is 0.

我认为此意外结果是由于打印unsigned long long int。你怎么printf()了unsigned long long int？

Answer 1

将ll（el-el）long-long修饰符与u（无符号）转换一起使用。（在Windows，GNU中运行）。printf("%llu", 285212672);

Answer 2

您可能需要使用inttypes.h库，让你的类型，如尝试 int32_t，int64_t，uint64_t等等，那么你可以使用它的宏，例如：uint64_t x;uint32_t y;printf("x: %"PRId64", y: %"PRId32"\n", x, y);这是“保证”不给你同样的麻烦的long，unsigned long long等等，因为你不必去猜测有多少位是每个数据类型。