将数字除以3，而不使用*，/，+，-，％运算符

Question

你会如何除以3为数字，没有使用*，/，+，-，%，运营商？

该数字可以签名也可以不签名。

Answer 1

您可以使用（取决于平台的）内联汇编，例如，对于x86 ：（也适用于负数）#include <stdio.h>int main() {&nbsp; int dividend = -42, divisor = 5, quotient, remainder;&nbsp; __asm__ ( "cdq; idivl %%ebx;"&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; : "=a" (quotient), "=d" (remainder)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; : "a"&nbsp; (dividend), "b"&nbsp; (divisor)&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; : );&nbsp; printf("%i / %i = %i, remainder: %i\n", dividend, divisor, quotient, remainder);&nbsp; return 0;}