用Javascript排序JSON对象
我一直在寻找排序这样的JSON对象的时间
{"results": [
{
"layerId": 5,
"layerName": "Pharmaceutical Entities",
"attributes": {
"OBJECTID": "35",
"FACILITYTYPE": "Pharmacy",
"FACILITYSUBTYPE": "24 Hr Pharmacy",
"COMMERCIALNAME_E": "SADD MAARAB PHARMACY",
},
"geometryType": "esriGeometryPoint",
},
{
"layerId": 5,
"layerName": "Pharmaceutical Entities",
"attributes": {
"OBJECTID": "1",
"FACILITYTYPE": "Pharmacy",
"FACILITYSUBTYPE": "24 Hr Pharmacy",
"COMMERCIALNAME_E": "GAYATHY HOSPITAL PHARMACY",
},
"geometryType": "esriGeometryPoint",
},
{
"layerId": 5,
"layerName": "Pharmaceutical Entities",
"attributes": {
"OBJECTID": "255",
"FACILITYTYPE": "Pharmacy",
"FACILITYSUBTYPE": "24 Hr Pharmacy",
"COMMERCIALNAME_E": "AL DEWAN PHARMACY",
},
"geometryType": "esriGeometryPoint",
}
]}
按“ COMMERCIALNAME_E”的字母顺序获取
{"results": [
{
"layerId": 5,
"layerName": "Pharmaceutical Entities",
"attributes": {
"OBJECTID": "255",
"FACILITYTYPE": "Pharmacy",
"FACILITYSUBTYPE": "24 Hr Pharmacy",
"COMMERCIALNAME_E": "AL DEWAN PHARMACY",
},
"geometryType": "esriGeometryPoint",
},
{
"layerId": 5,
"layerName": "Pharmaceutical Entities",
"attributes": {
"OBJECTID": "1",
"FACILITYTYPE": "Pharmacy",
"FACILITYSUBTYPE": "24 Hr Pharmacy",
"COMMERCIALNAME_E": "GAYATHY HOSPITAL PHARMACY",
},
"geometryType": "esriGeometryPoint",
},
{
"layerId": 5,
"layerName": "Pharmaceutical Entities",
"attributes": {
"OBJECTID": "35",
"FACILITYTYPE": "Pharmacy",
"FACILITYSUBTYPE": "24 Hr Pharmacy",
"COMMERCIALNAME_E": "SADD MAARAB PHARMACY",
},
"geometryType": "esriGeometryPoint",
}
]}
我找不到任何可以做到这一点的代码。谁能给我些帮助吗？
ibeautiful3回答
-
蝴蝶刀刀
function sortJsonArrayByProperty(objArray, prop, direction){ if (arguments.length<2) throw new Error("sortJsonArrayByProp requires 2 arguments"); var direct = arguments.length>2 ? arguments[2] : 1; //Default to ascending if (objArray && objArray.constructor===Array){ var propPath = (prop.constructor===Array) ? prop : prop.split("."); objArray.sort(function(a,b){ for (var p in propPath){ if (a[propPath[p]] && b[propPath[p]]){ a = a[propPath[p]]; b = b[propPath[p]]; } } // convert numeric strings to integers a = a.match(/^\d+$/) ? +a : a; b = b.match(/^\d+$/) ? +b : b; return ( (a < b) ? -1*direct : ((a > b) ? 1*direct : 0) ); }); }}sortJsonArrayByProperty(results, 'attributes.OBJECTID');sortJsonArrayByProperty(results, 'attributes.OBJECTID', -1);更新：请勿更改function sortByProperty(objArray, prop, direction){ if (arguments.length<2) throw new Error("ARRAY, AND OBJECT PROPERTY MINIMUM ARGUMENTS, OPTIONAL DIRECTION"); if (!Array.isArray(objArray)) throw new Error("FIRST ARGUMENT NOT AN ARRAY"); const clone = objArray.slice(0); const direct = arguments.length>2 ? arguments[2] : 1; //Default to ascending const propPath = (prop.constructor===Array) ? prop : prop.split("."); clone.sort(function(a,b){ for (let p in propPath){ if (a[propPath[p]] && b[propPath[p]]){ a = a[propPath[p]]; b = b[propPath[p]]; } } // convert numeric strings to integers a = a.match(/^\d+$/) ? +a : a; b = b.match(/^\d+$/) ? +b : b; return ( (a < b) ? -1*direct : ((a > b) ? 1*direct : 0) ); }); return clone;}const resultsByObjectId = sortByProperty(results, 'attributes.OBJECTID');const resultsByObjectIdDescending = sortByProperty(results, 'attributes.OBJECTID', -1); -
月关宝盒
首先提取JSON编码的数据：var data = eval(yourJSONString);var results = data['results'];然后使用自定义（用户）函数进行排序：results.sort(function(a,b){ //return a.attributes.OBJECTID - b.attributes.OBJECTID; if(a.attributes.OBJECTID == b.attributes.OBJECTID) return 0; if(a.attributes.OBJECTID < b.attributes.OBJECTID) return -1; if(a.attributes.OBJECTID > b.attributes.OBJECTID) return 1;});我假设您想按排序OBJECTID，但是您可以将其更改为按任何排序。 -
喵喔喔
您可以通过提供自定义比较功能作为的参数，对任何东西的有序数组进行排序Array.Sort()。var myObject = /* json object from string */ ;myObject.results.sort(function (a, b) { // a and b will be two instances of your object from your list // possible return values var a1st = -1; // negative value means left item should appear first var b1st = 1; // positive value means right item should appear first var equal = 0; // zero means objects are equal // compare your object's property values and determine their order if (b.attributes.COMMERCIALNAME_E < a.attributes.COMMERCIALNAME_E) { return b1st; } else if (a.attributes.COMMERCIALNAME_E < b.attributes.COMMERCIALNAME_E) { return a1st; } else { return equal; }});
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相关分类
JavaScript