根据ID连接值

Question

我有一个名为“结果”的表，数据如下：

Response_ID    Label

12147          It was not clear

12458          Did not Undersstand

12458          Was not resolved

12458          Did not communicate

12586          Spoke too fast

12587          Too slow

现在，我希望输出每个ID显示一行，并将Label中的值连接起来并用逗号分隔

我的输出应如下所示：

Response_ID    Label

12147          It was not clear

12458          Did not Undersstand,Was not resolved,Did not communicate

12586          Spoke too fast

12587          Too Slow

我怎样才能做到这一点：

Answer 1

您不能确定在子查询中没有order by语句的情况下串联的字符串的顺序。该.value('.', 'varchar(max)')部分用于处理Label包含XML不友好字符（如）的情况&。declare @T table(Response_ID int, Label varchar(50))insert into @T values(12147,          'It was not clear'),(12458,          'Did not Undersstand'),(12458,          'Was not resolved'),(12458,          'Did not communicate'),(12586,          'Spoke too fast'),(12587,          'Too slow')select T1.Response_ID,       stuff((select ','+T2.Label              from @T as T2              where T1.Response_ID = T2.Response_ID              for xml path(''), type).value('.', 'varchar(max)'), 1, 1, '') as Labelfrom @T as T1group by T1.Response_ID

Answer 2

DECLARE @Results TABLE(Response_ID INT, Label VARCHAR(80));INSERT @Results(Response_ID, Label)SELECT 12147,'It was not clear'UNION SELECT 12458,'Did not Undersstand'UNION SELECT 12458,'Was not resolved'UNION SELECT 12458,'Did not communicate'UNION SELECT 12586,'Spoke too fast'UNION SELECT 12587,'Too slow';WITH x AS (  SELECT Response_ID FROM @Results   GROUP BY Response_ID)SELECT x.Response_ID, Label = STUFF((SELECT ',' + Label    FROM @Results WHERE Response_ID = x.Response_ID    FOR XML PATH('')), 1, 1, '')    FROM x;