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5行代码无循环的解决方案定义之间的天数的方式与ChronoUnit.DAYS.between(start, end)表示4星期一至星期五之间存在天数的方式相同。由于我们只对工作日感兴趣,因此我们必须减去周末,因此从星期五到星期二会有2工作日(只需计算endDay - startDay并减去2周末)。1如果要包含结果,则添加到结果中,即不要间隔几天。我提出两种解决方案。第一个解决方案(5线,简短和隐秘):import java.time.*;import java.time.temporal.*;public static long calcWeekDays1(final LocalDate start, final LocalDate end) { final DayOfWeek startW = start.getDayOfWeek(); final DayOfWeek endW = end.getDayOfWeek(); final long days = ChronoUnit.DAYS.between(start, end); final long daysWithoutWeekends = days - 2 * ((days + startW.getValue())/7); //adjust for starting and ending on a Sunday: return daysWithoutWeekends + (startW == DayOfWeek.SUNDAY ? 1 : 0) + (endW == DayOfWeek.SUNDAY ? 1 : 0);}第二种解决方案:public static long calcWeekDays2(final LocalDate start, final LocalDate end) { final int startW = start.getDayOfWeek().getValue(); final int endW = end.getDayOfWeek().getValue(); final long days = ChronoUnit.DAYS.between(start, end); long result = days - 2*(days/7); //remove weekends if (days % 7 != 0) { //deal with the rest days if (startW == 7) { result -= 1; } else if (endW == 7) { //they can't both be Sunday, otherwise rest would be zero result -= 1; } else if (endW < startW) { //another weekend is included result -= 2; } } return result;}