使用纬度经度计算两点之间的距离？

Question

这是我的尝试，它只是我的代码片段：

final double RADIUS = 6371.01;

double temp = Math.cos(Math.toRadians(latA))

            * Math.cos(Math.toRadians(latB))

            * Math.cos(Math.toRadians((latB) - (latA)))

            + Math.sin(Math.toRadians(latA))

            * Math.sin(Math.toRadians(latB));

    return temp * RADIUS * Math.PI / 180;

我使用这个公式来获得经度和经度：

x = Deg + (Min + Sec / 60) / 60)

Answer 1

以上Dommer给出的Java代码给出了稍微不正确的结果，但如果您正在处理GPS轨道，则会出现小错误。以下是Java中Haversine方法的实现，它还考虑了两点之间的高度差异。/** * Calculate distance between two points in latitude and longitude taking * into account height difference. If you are not interested in height * difference pass 0.0. Uses Haversine method as its base. *  * lat1, lon1 Start point lat2, lon2 End point el1 Start altitude in meters * el2 End altitude in meters * @returns Distance in Meters */public static double distance(double lat1, double lat2, double lon1,        double lon2, double el1, double el2) {    final int R = 6371; // Radius of the earth    double latDistance = Math.toRadians(lat2 - lat1);    double lonDistance = Math.toRadians(lon2 - lon1);    double a = Math.sin(latDistance / 2) * Math.sin(latDistance / 2)            + Math.cos(Math.toRadians(lat1)) * Math.cos(Math.toRadians(lat2))            * Math.sin(lonDistance / 2) * Math.sin(lonDistance / 2);    double c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));    double distance = R * c * 1000; // convert to meters    double height = el1 - el2;    distance = Math.pow(distance, 2) + Math.pow(height, 2);    return Math.sqrt(distance);}