字符串分隔成数组

Question

问题描述
字符串分隔成数组，由于空格处过多，没有特别好的思路
当前实现方法
我觉得现在的实现方法实在有点麻烦
varstr='sourceIp==86.248.198.93&&sourceIp!=86.248.198.93||sourceIp==86.248.198.93||sourceIp!=86.248.198.93&&sourceIp==86.248.198.93:737&&sourceIp!=86.248.198.93:737||sourceIp==86.248.198.93:737||sourceIp!=86.248.198.93:737'
vararr=str.split('')
varnewArr=['']
arr.forEach(item=>{
letoldValue=newArr[newArr.length-1].trim()
if(item==='&&'||item==='||'){
newArr.push(item)
}else{
newArr[newArr.length-1]=oldValue+''+item
}
})
相关代码
'sourceIp==86.248.198.93&&sourceIp!=86.248.198.93||sourceIp==86.248.198.93||sourceIp!=86.248.198.93&&sourceIp==86.248.198.93:737&&sourceIp!=86.248.198.93:737||sourceIp==86.248.198.93:737||sourceIp!=86.248.198.93:737'
你期待的结果是什么？实际看到的错误信息又是什么？
["sourceIp==86.248.198.93","&&sourceIp!=86.248.198.93","||sourceIp==86.248.198.93","||sourceIp!=86.248.198.93","&&sourceIp==86.248.198.93:737","&&sourceIp!=86.248.198.93:737","||sourceIp==86.248.198.93:737","||sourceIp!=86.248.198.93:737"]

Answer 1

varstr='sourceIp==86.248.198.93&&sourceIp!=86.248.198.93||sourceIp==86.248.198.93||sourceIp!=86.248.198.93&&sourceIp==86.248.198.93:737&&sourceIp!=86.248.198.93:737||sourceIp==86.248.198.93:737||sourceIp!=86.248.198.93:737';consts=str.split(/\s*(?=\|{2}|\&{2})/);console.log(s);

Answer 2

要这样？conststr='sourceIp==86.248.198.93&&sourceIp!=86.248.198.93||sourceIp==86.248.198.93||sourceIp!=86.248.198.93&&sourceIp==86.248.198.93:737&&sourceIp!=86.248.198.93:737||sourceIp==86.248.198.93:737||sourceIp!=86.248.198.93:737'constarr=str.split(/\s+(?:&&|\|\|)\s+/)console.log(arr)