Scanner int 数据错误后 重新输入

Question

public int[] insertData() {

            System.out.println("要儲存的成績的數量");

            Scanner input = new Scanner(System.in);

            int k = input.nextInt();

            int[] a = new int[k];

            for (int i = 0; i < a.length - 1; i++) {

                    System.out.println("请输入第" + (i + 1) + "个数据：");

            try {

                    a[i] = input.nextInt();

            } catch (InputMismatchException e) {

                                System.out.println("输入的数据格式有误，不能有非数字！");

                                input.next();

                                i--;

                                continue;

                }

        }

            return a;

  }

// 开始的 int k   如果K 输入的是  字母  我不会处理。。。

Answer 1

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

Answer 2

把Scanner 那个流程封装成一个函数，判断输入是否是int值，不是的话再次调用函数。否则叫用户继续输入，直到获取k是int类型再进行下面的操作。具体实现靠你自己啦。