关于JSON.parse()的问题
//保存数据
function save(){
var contact = new Object;
contact.user_name = document.getElementById("user_name").value;
contact.mobilephone = document.getElementById("mobilephone").value;
contact.company = document.getElementById("company").value;
var str = JSON.stringify(contact);
localStorage.setItem(contact.mobilephone,str);
loadAll();
}
//查找数据
function find(){
var search_phone = document.getElementById("search_phone").value;
var name = localStorage.getItem(search_phone);
var mobilephone = localStorage.key(name);
var str = localStorage.getItem(contact.mobilephone);
var contact = JSON.parse(str);
var find_result = document.getElementById("find_result");
find_result.innerHTML = search_phone + "的机主是：" +contact.user_name;
}
在查询数据的代码中想要通过JSON.parse()来获取准确的储存在本地上的值,但是那里错误呢?
白衣染霜花4回答
-
千巷猫影
contact对象没有定义，localStorage.key方法乱用你的数据结构里头mobilephone===search_phone，不然localStorage取出来的是null哇，要判断一下的1234567function find(){ var str=localStorage[document.getElementById("search_phone").value]; if(str){ var contact=JSON.parse(str); document.getElementById("find_result").innerHTML=contact.mobilephone+"的机主是：" +contact.user_name; }} -
蓝山帝景
<html><body><h2>通过 JSON 字符串来创建对象</h3><p>text1: <span id="text1"></span><br />text2: <span id="text2"></span><br /></p><script type="text/javascript">var txt = '{"message":"the response was sucessful","type":"success"}';obj = JSON.parse(txt);document.getElementById("text1").innerHTML=obj.messagedocument.getElementById("text2").innerHTML=obj.type</script></body></html> -
慕姐8265434
$.ajax({type: "POST",url:"/i/ajax/get_cp_data",success: function(data) {if (data) {var json = $.parseJSON(data);cat_obj.success(json);}}});
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相关分类
Java