调用未定义的方法mysqli_stmt :: get_result
这是我的代码:
include 'conn.php';$conn = new Connection();$query = 'SELECT EmailVerified, Blocked FROM users WHERE Email = ? AND SLA = ? AND `Password` = ? ';$stmt = $conn->mysqli->prepare($query);$stmt->bind_param('sss', $_POST['EmailID'], $_POST['SLA'], $_POST['Password']);$stmt->execute(); $result = $stmt->get_result();
我在最后一行得到错误:调用未定义的方法mysqli_stmt :: get_result()
这是conn.php的代码:
define('SERVER', 'localhost');define('USER', 'root');define('PASS', 'xxxx');define('DB', 'xxxx');class Connection{ /** * @var Resource */ var $mysqli = null; function __construct(){ try{ if(!$this->mysqli){ $this->mysqli = new MySQLi(SERVER, USER, PASS, DB); if(!$this->mysqli) throw new Exception('Could not create connection using MySQLi', 'NO_CONNECTION'); } } catch(Exception $ex){ echo "ERROR: ".$e->getMessage(); } }}
如果我写这行:
if(!stmt) echo 'Statement prepared'; else echo 'Statement NOT prepared';
它打印'Statement NOT prepared'。如果我直接在IDE中运行查询替换?用值标记,它工作正常。请注意,$ conn对象在项目中的其他查询中正常工作。
请帮忙.......
RISEBY
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