C++编程中,怎么输入"Y"则继续运行下面代码?输入"N"就关闭程序？

Question

C++编程中,怎么输入"Y"则继续运行下面代码?输入"N"就关闭程序

Answer 1

#include <cstdlib>#include <iostream>#include <cmath>using namespace std;int main(int argc,char *argv[]){char ch;for(int i=0;;i++){cout <<"Enter:(Y-continue,N-exit):";cin >>ch;if(ch == 'N'){return 0;}else if(ch == 'Y'){continue; //换成要执行的代码}}system("PAUSE");return&nbsp;EXIT_SUCCESS;}

Answer 2

这样：char a = 'Y';...do{...cout<<"please input 'Y' or 'N'";}whlie(getchar() == a);

Answer 3

#include<iostream>using&nbsp;namespace&nbsp;std;&nbsp;int&nbsp;main(void){char&nbsp;b;start:{printf("输入(y/n)：");scanf("%c",&b);getchar();}if(b=='y')&nbsp;goto&nbsp;start;else&nbsp;return&nbsp;0;}