a.html有三个ajax方法(ajax1,ajax2,ajax3),先后访问a.php,如果ajax1访问a.php程序sleep(15)。请问这样会不会阻塞ajax2,ajax3的访问呢,原因是什么?a.html代码如下:vara=1;varb=1;varc=1;functionajax1(){$.get('a.php?from=a',function(){$('#ajax1').text(a);a++;ajax1();});}functionajax2(){$.get('a.php?from=b',function(){$('#ajax2').text(b);b++;ajax2();});}functionajax3(){$.get('a.php?from=c',function(){$('#ajax3').text(c);c++;ajax3();});}functionbeginAjax(){ajax1();ajax2();ajax3();}a.php代码如下:$from=$_GET['from'];if($from=='a'){sleep(15);}echo1;
交互式爱情
阿晨1998
相关分类