利用switch语句根据系统日期输出今天是星期几
利用switch语句根据系统日期输出今天是星期几
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慕村225694
#include<stdio.h>void main(){int a,b;printf("输入今天是星期几:");scanf("%d",&a);for(;a<1||a>7;){printf("输入错误，请输入1~7: ");scanf("%d",&a);}b=((100%7)+a)%7;switch(b){case 1: printf("100天后是星期一。\n");break;case 2: printf("100天后是星期二。\n");break;case 3: printf("100天后是星期三。\n");break;case 4: printf("100天后是星期四。\n");break;case 5: printf("100天后是星期五。\n");break;case 6: printf("100天后是星期六。\n");break;case 7: printf("100天后是星期日。\n");break;}} -
忽然笑
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"><HTML><HEAD><TITLE> New Document </TITLE><META NAME="Generator" CONTENT="EditPlus"><META NAME="Author" CONTENT=""><META NAME="Keywords" CONTENT=""><META NAME="Description" CONTENT=""></HEAD> <BODY><script type="text/javascript">var D = new Date();var sWeek = D.getDay();var temp = "";switch(sWeek){case 0:temp = "星期天";break;case 1:temp = "星期一";break;case 2:temp = "星期二";break;case 3:temp = "星期三";break;case 4:temp = "星期四";break;case 5:temp = "星期五";break;case 6:temp = "星期六";break;}document.write(temp);</script></BODY></HTML>
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