java 接口实现类编译显示不是抽象类，未覆盖抽象方法问题？

Question

接口代码：
interface Js{
public double mjjs();
public double zcjs();
}
两个实现类代码：
正方形
class Zfx implements Js{
double a;
public double mjjs(double a){
double zfxmj = a * a;
return zfxmj;
}
public double zcjs(double a){
double zfxzc = a * 4;
return a * 4; 
}
}
圆
class Circle implements Js{
double A = 3.14;
public double mjjs(double r){
double circlemj= A*r*r;
return circlemj;
}
public double zcjs(double r){
double circlezc = A*2*r;
return circlezc;
} 
}

测试类
class TestJs{
public static void main(String[] args){
Zfx zfx = new Zfx();
double zfxmj=zfx.mjjs(4.0);
double zfxzc=zfx.zcjs(4.0);
Circle circle =new Circle();
double circlemj=circle.mjjs(2.0);
double circlezc=circle.zcjs(2.0);
System.out.println(zfxmj);
System.out.println(zfxzc);
System.out.println(circlemj);
System.out.println(circlezc);
}
}

请大神帮我看下，哪里出问题了

Answer 1

你应该是重载了，你接口中的方法没有元素但继承后类中方法里有元素了interface Js{public double mjjs(double a);public double zcjs(double a);}class Zfx implements Js{double a;public double mjjs(double a){double zfxmj=a*a;return zfxmj;}public double zcjs(double a) {     double zfxzc=a*4;     return zfxzc; }}class Circle implements Js{double A = 3.14;public double mjjs(double r){double circlemj= A*r*r;return circlemj;}public double zcjs(double r){double circlezc = A*2*r;return circlezc;} }public class test {public static void main(String[] args){Zfx zfx = new Zfx();double zfxmj=zfx.mjjs(4.0);double zfxzc=zfx.zcjs(4.0);Circle circle =new Circle();double circlemj=circle.mjjs(2.0);double circlezc=circle.zcjs(2.0);System.out.println(zfxmj);System.out.println(zfxzc);System.out.println(circlemj);System.out.println(circlezc);}}

Answer 2

你这样写报错了吧，报错不就知道是什么问题了吗，你实现了接口，接口里的方法都是抽象方法，你重载了这个方法而没有重写这个方法