一个多层嵌套的json数据,我想取它每一个children下面的name值,请问怎么取?而且这个json的嵌套层数还可能会增加。

[
{
"children":[
],
"users":null,
"id":"//嘿嘿嘿",
"name":"嘿嘿嘿",
"nikeName":null,
"indexPeople":null,
"phone":"2232223",
"mailPhone":"2231113",
"ade":"故事的故事告诉",
"mailNumber":"1232333",
"parentId":"/"
},
{
"children":[
{
"children":[
],
"users":null,
"id":"//测试1234/测试1234565",
"name":"测试1234565",
"nikeName":null,
"indexPeople":null,
"phone":"3325663",
"mailPhone":"3326663",
"ade":"沙发沙发上地方",
"mailNumber":"325666",
"parentId":"//测试1234"
}
],
"users":null,
"id":"//测试1234",
"name":"测试1234",
"nikeName":null,
"indexPeople":null,
"phone":"3325663",
"mailPhone":"332552",
"ade":"发斯蒂芬斯蒂芬是",
"mailNumber":"326544",
"parentId":"/"
},
{
"children":[
{
"children":[
],
"users":null,
"id":"//违法监察机关/青白江执法队",
"name":"青白江执法队",
"nikeName":null,
"indexPeople":null,
"phone":"3325335",
"mailPhone":"3323663",
"ade":"公司公司归属感",
"mailNumber":"326322",
"parentId":"//违法监察机关"
}
],
"users":null,
"id":"//违法监察机关",
"name":"违法监察机关",
"nikeName":null,
"indexPeople":null,
"phone":"3325336",
"mailPhone":"3325336",
"ade":"的桑葚是的故事告诉",
"mailNumber":"326511",
"parentId":"/"
}
]
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浏览 1266回答 2
2回答

江户川乱折腾

写个递归方法来获取children里面name值,你最后想得到是个数组,[name1.name2,name3...],这样的格式,还是说数组里面是对象的格式呢?
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