python字典如何计算键值对的总数

Question

{'a':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),
'b':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),
'c':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),
'd':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),
'e':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),
'f':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456'),
'g':('123123','asdasd','123asd','000000','111111','123456','1234567','12345678','123456789','a123456')}
如上，键值对有70，使用len()方法只能得出7，求在最好不用FOR循环的情况用dict对象最优的自带方法使结果为70（如果有的话）

Answer 1

追求性能能的情况下，列表推导性能最高，循环次之，map最差所以写法应该是用列表推导更合适sum([len(_)for_ind.values()])

Answer 2

那你这是不算是计算键值对的数量啊...而是计算每个值的length之和，所以没有办法使用dict对象内置的东东来解决目前我想到的方法就是sum(map(lambdax:len(x)ifhasattr(x,"__len__")else1,v)//v是你的dict抛砖引玉吧