Java中用循环来这样创建对象，不是应该引用重名报错吗？为什么不报？

Question

循环第二次的时候，就有一个重名的my了呀？为什么还是能正常运行，不报错？

Answer 1

你的my定义的是局部变量，每执行一次for循环都重新定义了变量。即使你把变量放在循环外面定义，java中不会报错，只是变量存的地址会覆盖掉之前的变量。

Answer 2

直接上代码：public class Test {&nbsp; &nbsp; public static void main(String[] args) {&nbsp; &nbsp; &nbsp; &nbsp; for (int i = 0; i < 3; i++) {&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; Thread thread = new Thread();&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; thread.start();&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; System.out.println(thread.getName());&nbsp; &nbsp; &nbsp; &nbsp; }&nbsp; &nbsp; }}// 运行结果：// Thread-0// Thread-1// Thread-2如果你要指定名字，你应该这样来做：public class Test {&nbsp; &nbsp; public static void main(String[] args) {&nbsp; &nbsp; &nbsp; &nbsp; Thread thread = new Thread("我的线程");&nbsp; &nbsp; &nbsp; &nbsp; thread.start();&nbsp; &nbsp; &nbsp; &nbsp; System.out.println(thread.getName());&nbsp; &nbsp; }}//运行结果：//我的线程

Answer 3

my指向不同的MyThread实例对象罢了my ⇢ new MyThread() //老的↘ new Mythread() //新的