PHP词义化时间 idate

Question

从typecho中剥了一段词义化时间代码并按需做了修改，在测试中发现有个问题很纳闷：（
假如Unix时间戳$form与$now相差300,而它们处于不同的小时段idate(H),这样5分钟前的操作却显示为1小时前,然而在TE中却没有发现这现象^-!，
现在的问题是$between<3600而idate(H)相差1，请问如何修正？本人PHP门外汉，特不耻上问！
if($between<3600&&idate('H',$from)==idate('H',$now)){
functiondateWord($from){
$now=time();
$between=$now-$from;
$s=date('Y年m月d日H:i',$from);
if($between>0&&$between<86400&&idate('d',$from)==idate('d',$now)){
if($between<3600&&idate('H',$from)==idate('H',$now)){
if($between<60&&idate('i',$from)==idate('i',$now)){
$second=idate('s',$now)-idate('s',$from);
if(0==$second){
return'刚刚';
}else{
return''.$second.'秒前';
}
}
$min=idate('i',$now)-idate('i',$from);
return''.$min.'分钟前';
}
$hour=idate('H',$now)-idate('H',$from);
return''.$hour.'小时前';
}
}
源码如下
/**
*词义化时间
*
*@accesspublic
*@paramstring$from起始时间
*@paramstring$now终止时间
*@returnstring
*/
publicstaticfunctiondateWord($from,$now)
{
$between=$now-$from;
/**如果是一天*/
if($between>0&&$between<86400&&idate('d',$from)==idate('d',$now)){
/**如果是一小时*/
if($between<3600&&idate('H',$from)==idate('H',$now)){
/**如果是一分钟*/
if($between<60&&idate('i',$from)==idate('i',$now)){
$second=idate('s',$now)-idate('s',$from);
if(0==$second){
return_t('刚刚');
}else{
returnsprintf(_n('%d秒前','%d秒前',$second),$second);
}
}
$min=idate('i',$now)-idate('i',$from);
returnsprintf(_n('%d分钟前','%d分钟前',$min),$min);
}
$hour=idate('H',$now)-idate('H',$from);
returnsprintf(_n('%d小时前','%d小时前',$hour),$hour);
}
/**如果是昨天*/
if($between>0&&$between<172800&&(idate('z',$from)+1==idate('z',$now)||idate('z',$from)>2+idate('z',$now))){
return_t('昨天%s',date('H:i',$from));
}
/**如果是一个星期*/
if($between>0&&$between<604800&&idate('W',$from)==idate('W',$now)){
$day=intval($between/(3600*24));
returnsprintf(_n('%d天前','%d天前',$day),$day);
}
/**如果是*/
if($between>0&&$between<31622400&&idate('Y',$from)==idate('Y',$now)){
returndate(_t('n月j日'),$from);
}
returndate(_t('Y年m月d日'),$from);
}

Answer 1

因为你剥离出来的代码对小时只对同一小时的情况进行了判断，并未判断相邻小时但相差60分钟内的情况，因此，我加了一个gapHour的变量用来代表小时差，当时间相差60分钟内，做一个if判断，如果同一小时默认处理($gapHour==0)，相差一个小时时($gapHour==1)，再做相应的处理。functiondateWord($from){$now=time();$between=$now-$from;$s=date('Y年m月d日H:i',$from);$fromHour=idate('H',$from);$nowHour=idate('H',$now);$gapHour=$nowHour-$fromHour;if($between>0&&$between

Answer 2

额一来大段代码看着头晕，二来官方现在也不是很推荐用date()函数来操作时间对象了，所以我把整个的代码都改写了一下：functiondateWord($from,$now){$timezone=newDateTimeZone('Asia/Shanghai');$now=newDateTime($now,$timezone);$from=newDateTime($from,$timezone);$between=$now->diff($from);if(!$between->invert)returnfalse;/**如果超过了一年**/if($between->y)return$from->format('Y年m月d日');/**一年内大于七天**/if($between->days>6)return$from->format('n月j日');/**一个礼拜内但是大于两天**/if($between->days>1)return$between->format('%d天前');/**如果是昨天**/if($between->days)return$from->format('昨天H:i');/**如果一天之内超过一个小时**/if($between->h>1)return$between->format('%h小时前');if($between->i>1)return$between->format('%i分钟前');return$between->s?$between->format('%s秒前'):'刚刚';}functiondateWordToHtml($from,$now='now'){$dateWord=dateWord($from,$now);$from=newDateTime($from,newDateTimeZone('Asia/Shanghai'));$fromWord=$from->format('Y年m月d日H:i');return"$dateWord";}echodateWordToHtml("2014/4/149:32");dateWord()函数对应的是Typecho原版的返回，dateWordToHtml()函数则是对应你修改的那个函数（另外新建一个函数主要是方便其他人参考调用）。