c#如何解析json？

Question

{
"retcode":0,
"result":[
{
"poll_type":"message",
"value":{
"msg_id":32065,
"from_uin":2246865592,
"to_uin":1589188359,
"msg_id2":605408,
"msg_type":9,
"reply_ip":178848417,
"time":1352614319,
"content":[
[
"font",
{
"size":10,
"color":"000000",
"style":[
0,
0,
0
],
"name":"\u9ED1\u4F53"
}
],
"hi"
]
}
}
]
}请问如何用Newtonsoft.Json或其他类库取出hi这个值，感激不尽！

Answer 1

usingSystem;usingSystem.Collections.Generic;usingSystem.Linq;usingSystem.Text;usingNewtonsoft.Json;usingNewtonsoft.Json.Converters;usingNewtonsoft.Json.Serialization;usingNewtonsoft.Json.Linq;namespacecscliTest{publicclassFont{publicintsize;publicintcolor;publicstringname;publicListstyle=newList();}publicclassContent{publicstringhi;publicFontfont=newFont();}publicclassValue{publicintmsg_id;publicuintfrom_uin;publicuintto_uin;publicintmsg_id2;publicintmsg_type;publicintreply_ip;publicinttime;publicListcontent=newList();}publicclassResult{publicstringpoll_type;publicValuevalue;}publicclasssss{publicintretcode;publicListresult=newList();}publicclassTest{publicintm_a;publicinta{get;set;}}classProgram{staticvoidMain(string[]args){//测试数据sssa=newsss();a.retcode=0;Resultr=newResult();Valuev=newValue();Contentc=newContent();Fontf=newFont();f.size=10;f.color=0;f.style=newList(newint[]{0,0,0});f.name="xxx";c.font=f;c.hi="hello";v.msg_id=32065;v.from_uin=2246865592;v.to_uin=1589188359;v.msg_id2=605408;v.msg_type=9;v.reply_ip=178848417;v.time=1352614319;v.content.Add(c);r.value=v;a.result.Add(r);stringxx=JsonConvert.SerializeObject(a);Console.WriteLine(xx);//方法一（需定义上面那些类）sssa2=(sss)JsonConvert.DeserializeObject(xx);Console.WriteLine(a2.retcode);//方法二（不需定义上面那些类）JObjecto=(JObject)JsonConvert.DeserializeObject(xx);JTokeno2=o["result"][0];JTokeno3=o2["value"];JTokeno4=o3["content"][0];JTokeno5=o4["hi"];Console.WriteLine(o5.ToString());}}}感觉content后面的两个[[格式有问题，所以我这里的和你的格式有点差别，请注意。以前做过，今天翻了下，网上的太乱，以至于弄了挺久。

Answer 2

varser=newJavaScriptSerializer();returnser.Deserialize(json);JavaScriptSerializer类在System.Web.Script.Serialization需引入System.Web.Extensionsdll