javascript 事件返回值的传递问题
javascript 事件返回值的传递问题
30秒到达战场浏览 445回答 2
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千巷猫影
12345678910111213141516171819202122232425262728293031<html><head><script type="text/javascript">function loadXMLDoc(){var xmlhttp;if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); }else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); }xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("myDiv").innerHTML=xmlhttp.responseText; } }xmlhttp.open("GET","/ajax/test1.txt",true);xmlhttp.send();}</script></head><body><div id="myDiv"><h2>Let AJAX change this text</h2></div><button type="button" onclick="loadXMLDoc()">通过 AJAX 改变内容</button></body></html>
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JavaScript