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隔江千里
json_decode
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慕哥6287543
先转让数据格式为下面的(不知道还有没有精简的方法。。)
$arr = [
'1' => [
[
'month' => '2016-08',
'sum_money' => 250000,
],
[
'month' => '2016-09',
'sum_money' => 250000,
],
],
'2' => [
[
'month' => '2016-08',
'sum_money' => 250000,
],
[
'month' => '2016-09',
'sum_money' => 250000,
],
],
'3' => [
[
'month' => '2016-08',
'sum_money' => 250000,
],
[
'month' => '2016-09',
'sum_money' => 250000,
],
]
];
foreach ($arr as $name => $item) {
$series[] = [
'name' => $name,
'data' => array_column($item, 'sum_money')
];
}
$xAxis = array_column(array_pop($arr), 'month');
dump($xAxis);
$series = json_encode($series);
dump($series);
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九州编程
我思路是,你先把日期取出来,array_column这样就可以获取到日期数组,然后根据日期数组去遍历元数组获取统计数据,所有数据需要跟日期的数组顺序一致,然后json_encode返回给前端.
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吃鸡游戏
<?php
$array = [
['month'=>'2016-08', 'borrow_duration' => '1', 'sum_money'=>'1234'],
['month'=>'2016-08', 'borrow_duration' => '2', 'sum_money'=>'1231'],
['month'=>'2016-09', 'borrow_duration' => '1', 'sum_money'=>'2230'],
['month'=>'2016-09', 'borrow_duration' => '3', 'sum_money'=>'56723'],
];
$month = [];
$data = [];
foreach($array as $key => $value){
$month[$value['month']] = $value['month'];
$data[$value['borrow_duration']]['name'] = $value['borrow_duration'];
$data[$value['borrow_duration']]['data'][] = $value['sum_money'];
}
$month = array_values($month);
$data = array_values($data);
echo json_encode($month);
echo json_encode($data);
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德玛西亚99
echarts好像可以直接用json格式的
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撒科打诨
class SegmentFault{
public $array = array(
array('month' => '2016-03', 'borrow_duration' => '1', 'sum_money' => '230000'),
array('month' => '2016-04', 'borrow_duration' => '2', 'sum_money' => '240000'),
array('month' => '2016-05', 'borrow_duration' => '3', 'sum_money' => '250000'),
array('month' => '2016-06', 'borrow_duration' => '1', 'sum_money' => '260000'),
array('month' => '2016-07', 'borrow_duration' => '2', 'sum_money' => '270000'),
array('month' => '2016-08', 'borrow_duration' => '3', 'sum_money' => '280000')
);
public function echarts()
{
foreach ($this->array as $key => $value)
{
$res['data'][] = $value['month'];
$res[$value['borrow_duration']]['name'] = $value['borrow_duration'];
$res[$value['borrow_duration']]['data'][] = $value['sum_money'];
}
return $res;
}
}
$instance = new SegmentFault();$res = $instance->echarts();echo json_encode($res);