多选题评分算法 求指导

Question

多选题评分规则

每个正确选项都有得分权重，选正确一个给该正确选项得分权重的分值，选错一个，则总分为0

假如:正确答案ABC ，总分10分，权重分别为 20% 40% 40%

提交答案 ABC 得 （20%+40%+40%）* 10 = 10分

提交答案 AB 得 （20%+40%）* 10 = 6分

提交答案 ABD 得 0分

集思广益，如果可以请使用PHP作答

Answer 1

function selectScore(preAnswerScore,answer) { let totalScore = 0; let noScoreKey = []; let hasNoScoreKey = false; for(let key in preAnswerScore) { if(preAnswerScore[key] == 0){ noScoreKey.push(key); } } noScoreKey.map( item => { if(answer.includes(item)){ hasNoScoreKey = true; } }); if(hasNoScoreKey) { totalScore = 0; }else{ answer.map (item => { totalScore += preAnswerScore[item]; }); totalScore /= 10; } return totalScore; } let preAnswerScore = {a: 20, b: 40, c: 40, d: 0}; let answer = ['c','b','d'] console.log(selectScore(preAnswerScore, answer)); } js走一波，考虑到你其他选择题也适用

Answer 2

不会php， 用一下js // 选择的选项 const select = ['a','b','d'] // 分数 const score = { 'a': 20, 'b': 20, 'c': 60, 'd': 0 } // 根据所选 得到 分数如：abd 的到 20,20,0 const a = select.map(x => score[x]) // 如果 a里面有 0 直接返回 0 否则 reduce 后得到 分数 total = a.includes(0) ? 0 : a.reduce((total, i) => total+ (i *0.1) , 0)

Answer 3

思路，获得提交与答案的交集，如果交集个数不等于提交个数，则认为，存在选错的值，如果交集个数等于提交个数，遍历求分即可 <?php function multiSelectScore($answer, $wight, $allScore, $submit) { $score = 0; $answerWight = array_combine($answer, $wight); // 计算交集 $selects = array_intersect($answer, $submit); if(count($selects) === count($submit)) { // 遍历交集 foreach($selects as $key => $select) { $score += $answerWight[$select] * 0.01 * $allScore; } } return $score; } // 答案 $answer = ["A", "B", "C"]; // 权重 $wight = ["20","30","50"]; // 总分 $allScore = 10; // 提交的选项 $submit = ["A","C"]; $score = multiSelectScore($answer, $wight, $allScore, $submit); echo json_encode($score) . "\n";

Answer 4

function calc($result,$answer,$score){ $count = count($result); $d = array_diff($answer,$result); if($d){ return 0; } $c = array_diff($result,$answer); $lost = count($c); if(!$lost){ return $score; } switch ($count) { case 1: $per = [1=>1]; break; case 2: $per = [1=>0.4,2=>1]; break; case 3: $per = [1=>0.2,2=>0.6,3=>1]; break; default: $per = [1=>0.1,2=>0.5,3=>0.8,4=>1]; break; } $true = $count - $lost ; return $per[$true]*$score; } $result = ['A','B','C']; $answer = ['A','B']; $score = 10; echo calc($result,$answer,$score);

Answer 5

function check_score(array $answer, array $correct, $total_score){ $answer=array_flip($answer); $check=array_intersect_key($correct, $answer); return in_array($check, 0) ? 0 : array_sum($ckeck)*$total_score; } $answer为答案数组（['A', 'B', 'C']） $correct为正确答案数组（['A'=>0.2, 'B'=>0.4, 'C'=>0.4, 'D'=>0]） $total_score为总分 首先翻转$answer让选项成为key（['A'=>0, 'B'=>1, 'C'=>2]） 然后根据key计算$correct和$answer的交集$check，$check的key和value都保留$correct的。 检查$check的value中是否有0，有的话说明有错误答案，返回0分，否则计算$check的value的和，并乘以总分返回。