对于Laravel控制器修饰符的疑问

Question

为什么Laravel控制器使用protected修饰也可以正常访问？

protected function advert()
        {
            try {
                $result = $this->systemService->advert ();
                
                return $this->response->array (Response::return (200, '获取成功', $result));
            } catch (\Exception $e) {
                return $this->response->array (Response::return (0, $e->getMessage ()));
            }
        }

就算使用反射实例化也不能访问protected修饰的方法吧,laravel源码如下

$constructor = $reflector->getConstructor();
        // If there are no constructors, that means there are no dependencies then
        // we can just resolve the instances of the objects right away, without
        // resolving any other types or dependencies out of these containers.
        if (is_null($constructor)) {
    
            array_pop($this->buildStack);
    
            return new $concrete;
        }

        $dependencies = $constructor->getParameters();
        // Once we have all the constructor's parameters we can create each of the
        // dependency instances and then use the reflection instances to make a
        // new instance of this class, injecting the created dependencies in.
        $instances = $this->resolveDependencies(
            $dependencies
        );

        array_pop($this->buildStack);
        
        return $reflector->newInstanceArgs($instances);

Answer 1

Illuminate\Routing\Controller 这是laravel调用控制器方法的方法 public function dispatch(Route $route, $controller, $method) { $parameters = $this->resolveClassMethodDependencies( $route->parametersWithoutNulls(), $controller, $method ); if (method_exists($controller, 'callAction')) { return $controller->callAction($method, $parameters); } return $controller->{$method}(...array_values($parameters)); } Laravel通过controller继承的callAction去调用子类的指定方法，也就是我们希望调用的自定义方法。 public function callAction($method, $parameters) { return call_user_func_array([$this, $method], $parameters); } 因为是继承自父类，所以父类能调用子类的保护的方法也是自然的了。