jquery 返回实体对象怎么取值啊

Question

public String sayHello(){
HttpServletResponse response=ServletActionContext.getResponse(); 
response.setContentType("text/html;charSet=gbk"); 
try {
PrintWriter out = response.getWriter();
Book book=new Book();
book.setId(1);
book.setIsbn("1234");
book.setName("人中吕布");
out.print(book);
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} 
return null;
}
$(function(){
$("input[type=button]:eq(0)").click(function(){
var options = {
type:"post",
target: "#myTargetDiv",
//dataType:'script',
success: getsc
};
//ajax一步上传表单
$("#myForm").ajaxSubmit(options);
});
});
function getsc(data)
{
//var obj = $(data);
//var name = data.name
alert($(data));/* 这几种都取不到..*/
} 这是前台ajax提交,想取book对象的属性，应该怎么取啊?

Answer 1

如果你前面的配置没错的话:function getsc(data){var obj = $(data);alert(obj.find("name").text());}