kubernetes节点怎么自定义暴露端口

Question

kubernetes节点怎么自定义暴露端口

Answer 1

kubernetes节点怎么自定义暴露端口程序如下：void inv(int x[],int n) /*形参x是数组名*/{int temp,i,j,m=(n-1)/2;for(i=0;i<=m;i++){j=n-1-i;< BR> temp=x[i];x[i]=x[j];x[j]=temp;}return;}main(){int i,a[10]={3,7,9,11,0,6,7,5,4,2};printf("The original array:\n");for(i=0;i<10;i++)printf("%d,",a[i]);printf("\n");inv(a,10);printf("The array has benn inverted:\n");for(i=0;i<10;i++)printf("%d,",a[i]);printf("\n");}对此程序可以作一些改动。将函数inv中的形参x改成指针变量。&nbsp;