python列表相邻两元素组成元组

Question

demo = [1，2，3，4，5]
转换成
[(1,2),(3,4),(5,None)]

demo = [1]
转换成
[(1,None)]

成双的组合，单个的加None，为空时什么都不干

Answer 1

print map(None, *([iter([1,2,3,4,5])] * 2))#[(1, 2), (3, 4), (5, None)]print map(None, *([iter([1])] * 2))#[(1, None)]

Answer 2

list(dict(zip(demo[::2], demo[1::2] if len(demo)%2==0 else demo.append(None))).items())还是分2行吧 demo if len(demo)%2 == 0 else demo.append(None) list(dict(zip(demo[::2],demo[1::2])).items())

Answer 3

demo = [1, 2, 3, 4, 5] print(map(None, demo[::2], demo[1::2]))

Answer 4

python3 >>> from itertools import zip_longest as zipl >>> list(zipl(*([iter([1,2,3,4,5])] * 2))) [(1, 2), (3, 4), (5, None)] >>> list(zipl(*([iter([1])] * 2))) [(1, None)]