对象数组如何根据某个键值取交集

Question

a = [{name:'a',value:1},{name:'b',value:2},{name:'c',value:3}]
b = [{name:'a',value:1},{name:'b',value:2},{name:'d',value:4}]

a∩b = [{name:'a',value:1},{name:'b',value:2}]
两个对象数组根据name取交集，有什么好一点的实现方法呢？
直接循环感觉不够diao

Answer 1

underscore_.map(a.concat(b), 'name') // (6) ["a", "b", "c", "a", "b", "d"]