如何最优判断，特定的4个选项中至少有3个不为空，如下图和代码
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Document</title>
</head>
<body>
<script>
var arr = [];
var a = "a";
var b = "b";
var c = "c";
var d = "";
if(a != ""){
arr.push(a)
}
if(b != ""){
arr.push(b)
}
if(c !=""){
arr.push(c)
}
if(d != ""){
arr.push(d)
}
console.log(arr)
if(arr.length >=3){
console.log("aa")
}else{
console.log('bb')
}
</script>
</body>
</html>
LEATH浏览 544回答 5
5回答
-
温温酱
var a = '', b= '', c= 'c',d = 'a""'; var arr = [a, b, c, d]; var sum = 0; for(var i=0;i<arr.length;i++){ if(arr[i]!==''){ sum++; if(sum>3){ break; } } } console.log(sum) 想法是可以退出。。。够了三个就ok。当然如果就你开始那个数据结构，肯定也没啥搞头。还有filter之后拿length。 -
冉冉说
可以试试reduce var arr = [a,b,c,d] var count = arr.reduce(function (sum,currVal) {!!currVal&&sum++;return sum},0) -
动漫人物
filter函数就行吧。var arr = ['a', 'b', 'c', ''];if (arr.filter(item => item).length > 3) { ... } -
浮云间
var a = '', b= '', c= 'c',d = 'a""'; var reg = /("",|,"")/g; var arr = [a, b, c, d]; arr = JSON.stringify(arr); if(arr.match(arr).length > 1) { console.log('<3') } else { console.log('>=3') } 除了好看没什么软用 -
HUWWW
lst = ["a", "b", "c", ""] res = sum(map(len,lst))
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相关分类
Python