why cannot read int value from JTextField

JTextField t1 = new JTextField(" ");
String a = t1.getText(); 
int intA = Integer.parseInt(a); 
System.out.println(intA);

Error

java.lang.NumberFormatException: For input string: "1 "

附上我的代码

public class Testing extends JPanel {

    public int s;

    public Testing() {

        JPanel p = new JPanel();
        JTextField t1 = new JTextField(" ");
        JTextField t2 = new JTextField(" ");
        JTextField t3 = new JTextField(" ");
        JButton b3 = new JButton("result");

        p.add(t1);
        p.add(t2);
        p.add(t3);
        p.add(b3);
        add(p);

        b3.addActionListener(new ActionListener() {
            public void actionPerformed(ActionEvent e) {
                try {
                    String a = t1.getText();
                    int intA = Integer.parseInt(a);
                    System.out.println(intA);
                    // String b = t2.getText();
                    //t3.setText(a+"");
                } catch (NumberFormatException ignored) {
                    System.out.println(ignored);
                }
            }
        });
    }

    public static void main(String... arg) {
        Testing p = new Testing();
        JFrame frame = new JFrame();
        frame.add(p);
        frame.setLocationRelativeTo(null);
        frame.pack();
        frame.setVisible(true);
    }
}
尚方宝剑之说
浏览 379回答 2
2回答

神不在的星期二

谢谢@Sjs_k 的答案 把 JTextField t1 = new JTextField(""); 改去 JTextField t1 = new JTextField(5); 就行了
打开App,查看更多内容
随时随地看视频慕课网APP

相关分类

Java