json串转Map<String, List<Object>>,请问如何操作?

Question

如何将json串如下:
{
"1":[{"id":6397891,"rate":81,"type":2,"unitId":1,"userId":7133}, {"id":6397882,"rate":72,"type":1,"unitId":1,"userId":7133}],
"2":[{"id":6397906,"rate":90,"type":1,"unitId":2,"userId":7133}]
}
转换为:Map<String, List<Unit>> 类型
通过jackson,fastjson,jsoblib都可以,
求指点!

Answer 1

public static Map<String, Object> jsonToMap(JSONObject json) throws JSONException { Map<String, Object> retMap = new HashMap<String, Object>(); if(json != JSONObject.NULL) { retMap = toMap(json); } return retMap; } public static Map<String, Object> toMap(JSONObject object) throws JSONException { Map<String, Object> map = new HashMap<String, Object>(); Iterator<String> keysItr = object.keys(); while(keysItr.hasNext()) { String key = keysItr.next(); Object value = object.get(key); if(value instanceof JSONArray) { value = toList((JSONArray) value); } else if(value instanceof JSONObject) { value = toMap((JSONObject) value); } map.put(key, value); } return map; } public static List<Object> toList(JSONArray array) throws JSONException { List<Object> list = new ArrayList<Object>(); for(int i = 0; i < array.length(); i++) { Object value = array.get(i); if(value instanceof JSONArray) { value = toList((JSONArray) value); } else if(value instanceof JSONObject) { value = toMap((JSONObject) value); } list.add(value); } return list; }

Answer 2

哈哈，看来已经来晚了啊...题主已经采纳答案了嘛，不过lamdba的方式还是要强烈安利给题主哈，因为代码简单的很多（用的fastjson哈，不过其他应该也差不多） 思路就是，题主的json字符串其实总得来说就是一个key-value的形式，应该是满足了最终题主想要的Map<String, List<Unit>>的结构了，所以直接一个Collectors.toMap就搞定啦 Map<String, List<Unit>> result = JSONObject.parseObject(s) .entrySet().stream() .collect(Collectors.toMap(Map.Entry::getKey, entry -> JSONObject.parseArray(String.valueOf(entry.getValue()), Unit.class))); 然后...就完了噻...就这么点代码...（s就是你那个json字符串哈）