HashMap的无参构造函数是如何构造初始容量为16的容器的？

Question

HashMap无参构造函数如下：

    /**
     * Constructs an empty <tt>HashMap</tt> with the default initial capacity
     * (16) and the default load factor (0.75).
     */
    public HashMap() {
        this.loadFactor = DEFAULT_LOAD_FACTOR; // all other fields defaulted
    }

它是如何像它Javadoc中说的一样构造了一个初始容量为16的容器的？Node数组都不用初始化的么？至少加上一句

table = new Node<>[DEFAULT_INITIAL_CAPACITY];

才合乎常理吧！
请各位赐教！

Answer 1

注释说了在第一次使用的时候才会初始化 /** * The table, initialized on first use, and resized as * necessary. When allocated, length is always a power of two. * (We also tolerate length zero in some operations to allow * bootstrapping mechanics that are currently not needed.) */ transient Node<K,V>[] table; 初始化代码在 final Node<K,V>[] resize() 方法里面， Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap]; table指向这个newTab