php登陆模块无法跳转
写的登陆页面一直无法跳转到欢迎界面，大佬看下哪里不对。点击登陆还是显示登陆框，没有预想的欢迎语句。
感觉可能是session的使用出了问题，但是查不出来。
首页
<!DOCTYPE html><html><head> <meta charset="utf-8"> <title>ecshop</title> <link rel="stylesheet" href="https://cdn.staticfile.org/twitter-bootstrap/3.3.7/css/bootstrap.min.css"> <script src="https://cdn.staticfile.org/jquery/2.1.1/jquery.min.js"></script> <script src="https://cdn.staticfile.org/twitter-bootstrap/3.3.7/js/bootstrap.min.js"></script></head><div class="container"> <div class="row clearfix"> <div class="col-md-8 column"> <div class="page-header"> <h1> ECSHOP </h1> </div> </div> <div class="col-md-4 column"> <?php // 引入 functions.php 文件 require_once("loginfunction.php"); //登录状态显示用户名，未登录显示登录表单 $loginfc = new indexlogin(); $loginfc->loggedIn(); ?> </div> </div>loginfunction
<?phpclass indexlogin{function loggedIn(){ //通过 $_SESSION 来判断用户是否登录 if(empty($loggd)){ echo<<<LOG <form class="form-horizontal" method="post" action="loginaction.php"> ID<input type="text" class="form-control" name="id"><br> Password <input type="password" class="form-control" name="pass"><br> <input type="submit" value="ログイン"> </form>LOG; }else{ // 登录显示欢迎页面 echo 'Welcome, ' . $loggd; echo <<<BUT <input type="button" value="logout" onclick="logoutFunction()">BUT; } } }?>loginaction
<?php$user = "r.ko";$password = "123";$id = $_POST['id'];$pass = $_POST['pass']; $dbh = new PDO('mysql:host=localhost;dbname=user;charset=utf8', $user, $password); $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $sql = "select pass FROM id where id =" .$id; $stmt = $dbh->query($sql); $result = $stmt->fetchAll(PDO::FETCH_ASSOC) ; $url = "http://localhost/boot/index.php"; if(!empty($result)){ if($pass == $result[0]['pass']){ $_SESSION["id"] = $id; $_SESSION["loggd"] = 1; echo "<script language = 'javascript'type = 'text/javascript'>";echo " window.location.href = '$url' "; echo "</script>"; }else{ echo<<<LOW <div class="alert alert-danger" role="alert"> <a href="$url" class="alert-link">PASSERR TRY AGAIN</a> </div>LOW; }} else { echo<<<LOF <div class="alert alert-danger" role="alert"> <a href="$url" class="alert-link">ERR TRY AGAIN</a> </div>LOF; } $dbh = null;?>
川菜师傅浏览 2056回答 3
3回答
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林子懿
这个能不能写的清楚一点出现问题的原因不外乎这两个代码中出现错误判断逻辑出错没有走elsesession没有生效
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MySQL
PHP