帮忙看看下面的代码问题 看看最下面的输出结果对不对 简要说明理由

Question

publicclass Test1

 

    {

 

        private int _age=10;

 

        public int Age

 

        {

 

            get { return _age; }

 

            set { _age = value; }

 

        }

 

        public virtual void  Output1(string name)

 

        {

 

            name ="Test1";

 

            Console.Write("Test1.Output1 ：Name is "+ name);

 

        }

 

        public virtual void Output2(ref stringrefname)

 

        {

 

            refname = "Test1";

 

            Console.Write("Test1.Output2 ：Name is " + refname);

 

        }

 

    }

 

    public class Test2:Test1

 

    {

 

        private int _age=20;

 

        public override void Output1(stringname)

 

        {

 

            name ="Test2";

 

            Console.Write("Test2.Output1 ：Name is "+ name);

 

        }

 

        public new void Output2(ref stringrefname)

 

        {

 

            refname = "Test2";

 

            Console.Write("Test2.Output2 ：Name is " + refname);

 

        }

 

        }

 

        string name = "Name";

 

        string refname = "RefName";

 

        Test1 t1 = new Test2();

 

        t1.Output1(name);  //输出1？

 

        t1.Output2(ref refname);  // 输出2？

 

        Console.Write(name); // 输出3？

 

        Console.Write(refname); // 输出4？

 

        Test2 t2 = new Test2();

 

        Console.Write(t2.Age.ToString()); //输出5以及是否装箱？

 

        t2.Output2(ref refname);  //输出6

Answer 1

Test2类重写了Test1类的OutPut1方法，隐藏了OutPut2方法，因此t1.OutPut1(name)输出应该调用的是重写后的方法即t2中的方法，输出应为：est2.Output1 ：Name is Test2；t1.OutPut2(ref refname)输出应该是：Test1.Output2 ：Name is  Test1。Console.Write(name)输出为：Name;Console.Write(refName）应为Test2。Console.Write(t2.Age.ToString())不是很清楚。t2.Output2(ref refname)输出：Test2.Output2 ：Name is  test2