python函数中def func(*args)这里*的作用是什么?

Question

python函数中def func(*args)这里*的作用是什么?

Answer 1

引用可靠的我心我在的回答：def fun_var_args(farg, *args): print "arg:", farg for value in args: print "another arg:", value fun_var_args(1, "two", 3) # *args可以当作可容纳多个变量组成的list*args是多个变量组成的元组（tuples）附上代码：def count_number(*args):print(args)print(type(args))count_number('hgfh','dasda')