JS中 undefined " |=" 运算在Python中如何实现

Question

Javascript代码：

function rstr2binl(d) {

    for (var a = Array(d.length >> 2), b = 0; b < a.length; b++) {

        a[b] = 0;

    }

    for (b = 0; b < d.length * 8; b += 8){

        a[b >> 5] |= (d.charCodeAt(b / 8) & 255) << b % 32;

    }

    return a

}

Python代码：

def rstr2binl(d):

    a = [0] * (len(d) >> 2)

    for b in range(0, len(a), 1):

        a[b] = 0

    for b in range(0, len(d) * 8, 8):

        a[b >> 5] |= (ord(d[b / 8]) & 255 << b) % 32

    return a

rstr2binl("abc123456")

Python输出:Error list out of range

JS输出:[ 828596833, 892613426, 54 ]

在JS代码中有些步骤是用 undefined |= (d.charCodeAt(b / 8) & 255) << b % 32;

请问在Python中如何实现呢，或者有其他办法达到这个函数的功能吗

Answer 1

因为在js里面不会有列表的下标越界问题，比如a = [1, 2]a[0] 输出1a[1] 输出2a[2] 输出undefined在python里如果先定长列表的长度，你去访问a[2]肯定越界了def rstr2binl(d):&nbsp; &nbsp; a = [0] * ((len(d) >> 2) + 1)&nbsp; &nbsp; print a&nbsp; &nbsp; for b in range(0, len(d) * 8, 8):&nbsp; &nbsp; &nbsp; &nbsp; a[b >> 5] |= (ord(d[b / 8]) & 255) << b % 32&nbsp; &nbsp; return a