控制台程序怎么接受window 计划里面的程序啊

Question

针对一个程序，新建一个计划，计划里面有多个操作，每个操作都有参数。

以时间的方法触发执行，就是执行不了啊。求解！！

Answer 1

参数是直接可由args 获取就行了。对控件台应用程序不熟悉啊。class Program{static void Main(string[] args){string para1=(string)args.GetValue(0);}}

Answer 2

具体什么错误，把代码贴出来。先参考一下我这：class&nbsp;Parent { &nbsp;&nbsp;List<Child>&nbsp;_children&nbsp;=&nbsp;new&nbsp;List<Child>();&nbsp;&nbsp;public&nbsp;Parent() &nbsp;&nbsp;{ &nbsp;&nbsp;&nbsp;&nbsp;_children.Add(new&nbsp;Child()); &nbsp;&nbsp;&nbsp;&nbsp;_children.Add(new&nbsp;Child()); &nbsp;&nbsp;&nbsp;&nbsp;_children.Add(new&nbsp;Child());&nbsp;&nbsp;&nbsp;&nbsp;//&nbsp;Add&nbsp;handler&nbsp;to&nbsp;the&nbsp;child&nbsp;event &nbsp;&nbsp;&nbsp;&nbsp;foreach&nbsp;(Child&nbsp;child&nbsp;in&nbsp;_children) &nbsp;&nbsp;&nbsp;&nbsp;{ &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;child.TimerFired&nbsp;+=&nbsp;Child_TimerFired; &nbsp;&nbsp;&nbsp;&nbsp;} &nbsp;&nbsp;}&nbsp;&nbsp;private&nbsp;void&nbsp;Child_TimerFired(object&nbsp;sender,&nbsp;EventArgs&nbsp;e) &nbsp;&nbsp;{&nbsp;&nbsp;&nbsp;&nbsp;//&nbsp;One&nbsp;of&nbsp;the&nbsp;child&nbsp;timers&nbsp;fired&nbsp;&nbsp;&nbsp;&nbsp;//&nbsp;sender&nbsp;is&nbsp;a&nbsp;reference&nbsp;to&nbsp;the&nbsp;child&nbsp;that&nbsp;fired&nbsp;the&nbsp;event&nbsp;&nbsp;} }class&nbsp;Child {&nbsp;&nbsp;public&nbsp;event&nbsp;EventHandler&nbsp;TimerFired;&nbsp;&nbsp;protected&nbsp;void&nbsp;OnTimerFired(EventArgs&nbsp;e) &nbsp;&nbsp;{&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;&nbsp;if&nbsp;(TimerFired&nbsp;!=&nbsp;null) &nbsp;&nbsp;&nbsp;&nbsp;{ &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;TimerFired(this,&nbsp;e); &nbsp;&nbsp;&nbsp;&nbsp;} &nbsp;&nbsp;}&nbsp;&nbsp;//&nbsp;This&nbsp;is&nbsp;the&nbsp;event&nbsp;that&nbsp;is&nbsp;fired&nbsp;by&nbsp;your&nbsp;current&nbsp;timer&nbsp;mechanism &nbsp;&nbsp;private&nbsp;void&nbsp;HandleTimerTick(...) &nbsp;&nbsp;{ &nbsp;&nbsp;&nbsp;&nbsp;OnTimerFired(EventArgs.Empty); &nbsp;&nbsp;} }