function ajaxfen1(num,jsonr){
var url1=globalServer+'/workorder/kcWorkorder/list/ajax?type=1&pageNo='
var json1=jsonr
$.ajax({
type:"POST",
url:url1+num,
async:true,
data:jsonr,
dataType:'json',
success:function(data){
var pagedata=data
var total=pagedata.totalRevenue
var list=pagedata.list
var html=''
var pageers=Math.ceil(pagedata.count/pagedata.pageSize)
$('.page-count21').html('共'+pagedata.count+'条')
$('.app1').html('收入总计:'+total+'元')
for (var i=0;i<list.length;i++) {
大概代码是这样的。但是每次JQ都会默认帮我变成get方式。我想用post--
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