想知道这两层循环中i，和j的变化，里外层循环是怎么走的?

Question

               for (let i = 0; i < this.temp1.length; i++) {
                        let found = false;                        for (let j = 0; j < combination_name_list.length; j++) {                            if (combination_name_list[j] == this.temp1[i].name) {
                                found = true;
                            }                    if (j == combination_name_list.length - 1 && found == false) {                                this.combination.push({                                    "name": this.temp1[i].name,                                    "rows1": this.temp1[i].rows,                                    "rows2": [],                                    "type": this.temp1[i].type
                                });
                            }
                        }
                    }

想知道这两层循环中i，和j的变化，里外层循环是怎么走的，以及这段代码的意思，只能看懂一半!

Answer 1

这个是取差集var temp1 = [{name:"a"},{name:"d"},{name:"c"}];var combination_name_list = ['a']; //结果var combination = [{name:"d"},{name:"c"}];combination_name_list 中存的是 temp1 的 name就是拿着 temp1 中 第一项 去 combination_name_list 中找 找到了 不操作 ，没找到 将这一项加进 新数组combination以此类推 第二项 。。。