ES6继承涉及到多个变量如何解决？

Question

'use strict';

class Person {

    // 构造函数，实例化的时候将会被调用，如果不指定，那么会有一个不带参数的默认构造函数.

    constructor(name) {

        this.name = name;

    }

    // printout 是原型对象上的方法(函数)

    personPrintOut() {

        console.log('name:' + this.name);

    }

}

// console.log(Animal('A',50));//ERROR Class constructor Animal cannot be invoked without 'new'

var A = new Person('A');

A.personPrintOut();

// 继承

class People extends Person {

    constructor(name, age) { //构造函数

        super(name);    //调用父类构造函数

        this.age = age;

    }

    peoplePrintOut() {

        console.log('name:' + this.name + ',age:' + this.age);

    }

}

var B = new People('B', 20);

B.peoplePrintOut();

//继承

class human extends People {

    constructor(name, age, height) { //构造函数

        super(name, age);    //调用父类构造函数

        this.height = height;

    }

    humanPrintOut() {

        console.log('name:' + this.name + ',age:' + this.age + ',height:' + this.height);

    }

}

var C = new human('c', 20, 200);

C.humanPrintOut();

Answer 1

rest参数 + 解析构constructor(...args) {    super(...args); }