Mysql查询数据返回排序

Question

例如有这样一条语句

select uid from user where uid = 70 or uid =68 or uid = 69;

mysql返回的是

68
69
70

如何让mysql返回

70
68
69

这样的结果,就是按照where的条件先后来返回.

Answer 1

select uid from user where uid in( 70 ,68 , 69) order by fine_in_set('uid','70,68,69');

Answer 2

SELECT id, nameFROM mytableWHERE name IN ('B', 'A', 'D', 'E', 'C')ORDER BY FIELD(name, 'B', 'A', 'D', 'E', 'C')