eclipse中分页问题

Question

这是后台控制层的分页代码

@RequestMapping("/findcustomer")//实现分页查询
@ResponseBody
public MyAjaxResult findCustomer(Integer adminId,String search,Integer currentPage,Integer pageSize){

PageModel pageModel;
try {
pageModel = cusService.findList(adminId,search,currentPage,pageSize);

return MyAjaxResult.success(pageModel);
} catch (Exception e) {

e.printStackTrace();
return MyAjaxResult.fail_300("查询失败");
} 
}

怎样在JSP页面这段代码实现分页查询

getCustomerListAjax();//模糊查询和查看全部
function getCustomerListAjax(cur) {
$.ajax({
url:"${pageContext.request.contextPath}/loginAction/get_customerList",
type:"post",
data:$("#seachForm").serialize(),
dataType:"json",
success: function(data){
if(data.code==200){
console.log(data);

$('#courseTypeWrap').html(template('courseTypeTest', data));
}else{
layer.open({
title: '警告！', 
content: data.msg 
,yes: function(index, layero){
//按钮【按钮一】的回调
window.location.href="${pageContext.request.contextPath}/loginAction/login"
}
});
}
}
});
}

Answer 1

是哪一部分不会，前端写隐藏input存页数，传到后端根据每页数据数量算出第a条数据到第几b条数据，sql中limit a,b