LinkButton 弹出新页面,谢谢

Question

LinkButton lb = new LinkButton();
                    lb.Text = MM.GetComeName(id).Tables[0].Rows[i]["CName"].ToString();
                    lb.PostBackUrl = "~/Chat.aspx?name="+lb.Text.Trim()+"&uid="+id;
                    AccordionPane.Controls.Add(lb);

Answer 1

直接拼出一个超链接字符串吧