python写个方法,只要有一项不在就返回False

Question

def contains( s, items ):
""" s为源，若items中每一项都存在于s中，则返回True；items中只要有一项不存在于s中，就返回False """

Answer 1

def contains(s, items):         for item in items:                 if item not in s:                         return False         return True

Answer 2

1, 使用all()2, 使用子集1234567def&nbsp;contains(s,&nbsp;items):&nbsp;&nbsp;&nbsp;&nbsp;return&nbsp;all([i&nbsp;in&nbsp;s&nbsp;for&nbsp;i&nbsp;in&nbsp;items])&nbsp;def&nbsp;contains2(s,&nbsp;items):&nbsp;&nbsp;&nbsp;&nbsp;return&nbsp;set(items)&nbsp;<&nbsp;set(s)&nbsp;print(contains2([1,&nbsp;2,&nbsp;3],&nbsp;[1,&nbsp;2,&nbsp;4]))