python 怎么输出下图的字符表

Question

Answer 1

m=32 n=32 for i in range((127-32+1)//16*2):     if i%2==0:         print('chr:'+'\t',end='')         for j in range(m,16+m):             print(chr(j)+'\t',end='')         m += 16     if i%2==1:         print('asc:'+'\t',end='')         for k in range(n,16+n):             print(str(k)+'\t',end='')         n += 16     print('')