python3中字符编码的问题？
Traceback (most recent call last):
File "restzhong.py", line 183, in <module>
caidan()
File "restzhong.py", line 43, in caidan
selected()
File "restzhong.py", line 129, in selected
s1=f.read()
File "/usr/local/Cellar/python/3.6.5/Frameworks/Python.framework/Versions/3.6/lib/python3.6/encodings/ascii.py", line 26, in decode
return codecs.ascii_decode(input, self.errors)[0]
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc2 in position 0: ordinal not in range(128)
这错误啥意思啊？mac下sublimetext报出来的
money=0
money2=0
class Lunch:
def __init__(self):
self.cus=Customer()
self.emp=Employee()
def order(self,foodName):
self.cus.placeOrder(foodName,self.emp)
def result(self):
#ask the Customer what kind of food it has
self.cus.printFood()
class Customer:
def __init__(self):#initialize my food to none
self.food=None
def placeOrder(self,foodName,employee):#place order with an Employee
self.food=employee.takeOrder(foodName)
def printFood(self): #print the name of my food
print(self.food.name)
class Employee:
def takeOrder(self,foodName) :#return a Food,wih requested name
return Food(foodName)
class Food:
def __init__(self,name):#store food name
self.name=name
if __name__=='__main__':
def caidan():
print("编号 菜 名 价格 ")
print("1 肉末茄子 17 ")
print("2 麻婆豆腐 9 ")
print("3 青椒土豆丝 8 ")
print("4 肉夹馍+凉皮 15 ")
print("5 大盘鸡 30 ")
print("6 蘑菇炒油菜 12 ")
selected()
def istrue(num):
try:
int(num)
return True
except ValueError:
return False
def dian(s,context):
global money
global money2
f2=open('aaaaa.txt','w')
f2.write(context)
f3=open('money.txt','r')
if s=='1':
f2.write("肉末茄子*(1) 17元"+"\n")
money1=f3.read()
x=Lunch()
x.order('肉末茄子')
x.result()
if istrue(money1):
money2=17+int(money1)
else:
money2=17
elif s=='2':
f2.write("麻婆豆腐*(1) 9元"+"\n")
money1=f3.read()
y=Lunch()
y.order('麻婆豆腐')
y.result()
if istrue(money1):
money2=9+int(money1)
else:
money2=9
elif s=='3':
f2.write("青椒土豆丝*(1) 8元"+"\n")
money1=f3.read()
z=Lunch()
z.order('青椒土豆丝')
z.result()
if istrue(money1):
money2=8+int(money1)
else:
money2=8
elif s=='4':
f2.write("肉夹馍+凉皮*(1) 15元"+"\n")
money1=f3.read()
d=Lunch()
d.order('肉夹馍+凉皮')
d.result()
if istrue(money1):
money2=23+int(money1)
else:
money2=23
elif s=='5':
f2.write("大盘鸡*(1) 30元"+"\n")
money1=f3.read()
e=Lunch()
e.order('大盘鸡')
e.result()
if istrue(money1):
money2=8+int(money1)
else:
money2=8
elif s=='6':
f2.write("蘑菇炒油菜*(1) 12元"+"\n")
money1=f3.read()
f=Lunch()
f.order('蘑菇炒油菜')
f.result()
if istrue(money1):
money2=12+int(money1)
else:
money2=12
f3=open('money.txt','w')
f2=open('aaaaa.txt','w')
f2.write(context)
f3.write(str(money2))
f2.close()
f3.close()
def selected():
f=open("aaaaa.txt","r")
s1=f.read().decode()
f.close()
print(" ")
print("已点菜品："+"\n"+s1)
f3=open('money.txt','r')
moneynum=f3.read()
f3.close()
print("小计："+moneynum)
print(" ")
selete=input("请选择您喜爱的菜品")
dian(selete,s1)
one=input("确认订单请按y，退出请按n，按任意键继续点单")
if one=='y':
f=open("aaaaa.txt","r")
s1=f.read()
f.close()
print(" ")
print("所有菜品："+"\n"+s1)
f3=open('money.txt','r')
moneynum=f3.read()
f3.close()
print("小计："+moneynum)
if istrue(moneynum):
print("此次订单需支付："+str(moneynum))
f3=open('money.txt','w')
f3.write("")
f2=open('aaaaa.txt','w')
f2.write("")
f2.close()
f3.close()
print("订单完成，祝您用餐愉快")
else :
print("您尚未选择商品")
elif one=='n':
print("退出成功！")
f3=open('money.txt','w')
f3.write("")
f2=open('aaaaa.txt','w')
f2.write("")
f2.close()
f3.close()
else :
selected()
print("<<<<<<<<<<欢迎来到外卖点餐系统>>>>>>>>>")
print("1.查看菜单")
print("2.退出")
selectone=input("请输入您的选择")
print(" ")
if selectone =='1':
caidan()
else :
print("成功退出")
qq_訫恋_0浏览 1851回答 6
6回答
-
qq_晓歌_0
可能是money.txt文件编码问题，encode，decode试试 -
相信光变成光
BUZHIDAO -
Glitterior
把代码发上来啊
随时随地看视频慕课网APP
相关分类
Python