关于一个构造方法中this()和super()的执行顺序?

Question

我在一个构造方法中调用第二个自身的构造方法,第二个自身构造方法中又包含一个super(),那么想知道在第一个自身构造方法中有没有隐式的super(),父类对象应该是优先于子类对象在堆内存里面出现的吧?最后究竟创建了几个父类对象
class Person {
 private String name;
 private String location;

 Person(String name) {
   this.name = name;
   location = "beijing";
 }

 Person(String name,String location) {
   this.name = name;
   this.location = location;
 }

 public String info() {
   return
     "name: "+name+
     " location: "+location;
 }}class Student extends Person {
   private String school;
   Student(String name,
String school) {
       this(name,"beijing", school);
   }
   Student(String n,String l
,String school) {
       super(n,l);
       this.school = school;
   }
   public String info() {
       return super.info()+
 " school: "+school;
   }}public class TestTeacher {
   public static void main(String[] args) {
   Student s1 = new Student("C","S1");
      System.out.println(s1.info());

   }}

Answer 1

Student(n, s)这个构造器里显式调用this()，抑制隐式super()，追溯到Student(n, l, s)里，没有显式this()调用，则隐式调用super()，即Person(n, l)在以上三个构造器里添加打印语句，结果如下：Person(n, l) establishedStudent(n, l, s) establishedStudent(n, s) established调用顺序一目了然