jq if判断jq元素left值失效问题求解

想做个手机网页的左边侧边栏，

代码：

<!DOCTYPE html>
<html>
<head>
   <meta charset="utf-8">
   <title></title>
   <script src="jq.js"></script>
</head>

<style type="text/css">
*{padding: 0;margin:0;}
body,html{width: 100%;height: 100%;}
.wrap{width: 100%;height: 100%;position:fixed;top: 0;bottom: 0;left: 0;right: 0;background: #000}
.wlef{width: 70%;z-index: 1;height: 100%;background: #ff0000}
.wright{width: 100%;height: 100%;background: #fff;z-index: 9999;position: absolute;top: 0;left: 0%;}
</style>
<body>
<div class="wrap">
   <div class="wlef">234234234342</div>
   <div class="wright"><a href="javascript:void(0)">关闭左边菜单</a></div>
   <script type="text/javascript">

   $(".wright a").click(function(){
       var left = $(".wright").css('left')
       alert($(".wright").css('left'))
       if(!$(".wright").css('left') >= 0){

           $(".wright").animate({left:'70%'},500);
       }else{
           $(".wright").animate({left:'0'},500);

       }

   });
   </script>
</div>

</body>
</html>

不知道为什么判断wright的left值大于0的时候就是不会动，问题求解

慕村1106498

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