多线程求解决下 谢谢大家!!!
class ThreadTest01 implements Runnable {
int num = 100;
// 2、覆盖接口中的run方法。。
@Override
public void run() {
while (true) {
/*
* 格式: synchronized(锁对象){ //需要同步的代码 }
*/
synchronized (Demo1.class) {
if (num<=0) {
break;
}
try {
Thread.sleep(1);
System.out.println(
Thread.currentThread().getName() + "出售了" + (1000 - num + 1) + "张票，还剩余：" + (--num) + "张");
/*
* this.notify(); this.wait();
*/
} catch (InterruptedException e) {
e.printStackTrace();
}
}
请问以上代码块
if (num<=0) {
break;
}
为什么不能改成
if (num>0) {
}
当使用该过后的 回出现负数是怎么回事啊?
慕姐8946757浏览 1419回答 3
3回答
-
慕的地8582982
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相关分类
Java