C语言编程时候的运行问题！求大佬指教！

Question

编程统计输入的字符串中数字字符出现的次数，不知道为啥结果不对！

Answer 1

ch[i]的话是字符型，然后放在a[ch[i]]就不对了，改成a[ch[i]-'0']

Answer 2

#include <stdlib.h>#include <stdio.h>int main(int arg,char * args){ char ch[80]; int count = 0; //用来统计字符出现次数 printf("请输入你的字符.\n"); int i = 0; for(i = 0;i < strlen(ch);i ++) { gets(ch); } while(ch[i] != ＇＼０＇) { if(ch[i] == ＇c＇)  //此处判断为假设你要查找的字符是c { count++; } } printf("字符c出现的次数为%d次！\n",count); /*以上代码中可能出现的函数使用方法不是很正确，毕竟是用记事本写的代码。如便难以出错请查询函数用法自行改正。。。。。。。 */ return 0; }

Answer 3

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Answer 4

1071187719428751842054115740983064342997674004128282851518818510865108208421955265397873536403708436517434066430730985486747682486308438632081707163243743909373588238361335256920913828985092012804327027258687810351853295357383194217769354093943329279286866424065790208435351932052805899538504847197290670894674182564658210934

Answer 5

8503291918333616004015607164105594865416984215699998754665101327867681582628798564062847483222113607977313782740116051791368437619555067426903544444678867417602396942352985689935423346978320452009495094845656598595060321209043491708072934096380493164273998540759651896025043525965555541762338847341492174794116290521991099959

Answer 6

写的好烂，a[ch[i]]++是什么鬼，单单就这个数组下标越界就什么都不说了，为什么最后还要用一个for，你是要上天吗？

Answer 7

buzhidao o 

Answer 8

第一个for循环，应该改为i++,保证循环次数10次。另外while循环下的if条件判断不对，你要打印的是字符出现的次数，a[10]这个数组其实没必要。定义一个变量统计就可以，打印的语句也有问题。

Answer 9

rrrr

Answer 10

hhh