为什么我这里的window.onload加载不了两个函数的？只有f1（）；有效果，f2()；没有。求解决
function f1() {
var container = document.getElementById('container1');
var list = document.getElementById('list1');
var buttons = document.getElementById('buttons1').getElementsByTagName('span');
var prev = document.getElementById('prev1');
var next = document.getElementById('next1');
var index = 1;
var len = 2;
var animated = false;
var interval = 3000;
var timer;
function animate (offset) {
if (offset == 0) {
return;
}
animated = true;
var time = 600;
var inteval = 10;
var speed = offset/(time/inteval);
var left = parseInt(list.style.left) + offset;
var go = function (){
if ( (speed > 0 && parseInt(list.style.left) < left) || (speed < 0 && parseInt(list.style.left) > left)) {
list.style.left = parseInt(list.style.left) + speed + 'px';
setTimeout(go, inteval);
}
else {
list.style.left = left + 'px';
if(left>-260){
list.style.left = -260 * len + 'px';
}
if(left<(-260 * len)) {
list1.style.left = '-260px';
}
animated = false;
}
}
go();
}
function showButton() {
for (var i = 0; i < buttons.length ; i++) {
if( buttons[i].className == 'on'){
buttons[i].className = '';
break;
}
}
buttons[index - 1].className = 'on';
}
function play() {
timer = setTimeout(function () {
next.onclick();
play();
}, interval);
}
function stop() {
clearTimeout(timer);
}
next.onclick = function () {
if (animated) {
return;
}
if (index == 2) {
index = 1;
}
else {
index += 1;
}
animate(-260);
showButton();
}
prev.onclick = function () {
if (animated) {
return;
}
if (index == 1) {
index = 2;
}
else {
index -= 1;
}
animate(260);
showButton();
}
for (var i = 0; i < buttons.length; i++) {
buttons[i].onclick = function () {
if (animated) {
return;
}
if(this.className == 'on') {
return;
}
var myIndex = parseInt(this.getAttribute('index'));
var offset = -260 * (myIndex - index);
animate(offset);
index = myIndex;
showButton();
}
}
container.onmouseover = stop;
container.onmouseout = play;
play();
}
function f2() {
var container = document.getElementById('container');
var list = document.getElementById('list');
var buttons = document.getElementById('buttons').getElementsByTagName('span');
var prev = document.getElementById('prev');
var next = document.getElementById('next');
var index = 1;
var len = 3;
var animated = false;
var interval = 3000;
var timer;
function animate (offset) {
if (offset == 0) {
return;
}
animated = true;
var time = 300;
var inteval = 10;
var speed = offset/(time/inteval);
var left = parseInt(list.style.left) + offset;
var go = function (){
if ( (speed > 0 && parseInt(list.style.left) < left) || (speed < 0 && parseInt(list.style.left) > left)) {
list.style.left = parseInt(list.style.left) + speed + 'px';
setTimeout(go, inteval);
}
else {
list.style.left = left + 'px';
if(left>-440){
list.style.left = -440 * len + 'px';
}
if(left<(-440 * len)) {
list.style.left = '-440px';
}
animated = false;
}
}
go();
}
function showButton() {
for (var i = 0; i < buttons.length ; i++) {
if( buttons[i].className == 'on'){
buttons[i].className = '';
break;
}
}
buttons[index - 1].className = 'on';
}
function play() {
timer = setTimeout(function () {
next.onclick();
play();
}, interval);
}
function stop() {
clearTimeout(timer);
}
next.onclick = function () {
if (animated) {
return;
}
if (index == 3) {
index = 1;
}
else {
index += 1;
}
animate(-440);
showButton();
}
prev.onclick = function () {
if (animated) {
return;
}
if (index == 1) {
index = 3;
}
else {
index -= 1;
}
animate(440);
showButton();
}
for (var i = 0; i < buttons.length; i++) {
buttons[i].onclick = function () {
if (animated) {
return;
}
if(this.className == 'on') {
return;
}
var myIndex = parseInt(this.getAttribute('index'));
var offset =-440 * (myIndex - index);
animate(offset);
index = myIndex;
showButton();
}
}
container.onmouseover = stop;
container.onmouseout = play;
play();
}
function addLoadEvent(func) {
var oldonload = window.onload;
if (typeof window.onload != 'function') {
window.onload = func;
} else {
window.onload = function() {
oldonload();
func();
}
}
}
addLoadEvent(f1);
addLoadEvent(f2);
宝慕林62936601回答
-
一诺yinol
window.onload 能加载两个方法的，在执行 f1() 的时候，return了！
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相关分类
JavaScript